# How to solve this problem on percentage calculation?

Fresh fruits contain 75% while dry fruits contain 20% water. If the weight of dry fruits is 300 kg what was its total weight when it was fresh?

Doubt: I really do not understand what to equate.

• I would start by looking at what we have right now. We have a pile of fruits (incl. 20% water) which weighs 300 kg. We know that 80% of that is the "pure" fruits, so that's 0.8*300=240 kg. Now, let's look at the initial state. In the initial state, the weight of the "pure" fruits was still 240 kg but that's only 25% of the total mass. If 240 kg is 25% of the total mass, what is the total mass? Aug 4, 2021 at 9:28

Let $$x_1 = 300$$ (kg) and let $$x_2$$ be the total mass you are looking for.
From your first sentence, you can write $$(1-0.75)x_2 = (1-0.20)x_1$$. This is the ratio of pure fruits they both have. So from $$x_1$$, $$80$$% is pure fruit, which is $$240$$. This gives $$0.25x_2 = 240$$, which leads to $$x_2 =$$ total mass $$=960$$kg