Let $G$ be a non abelian group of order $36.$ Show that there is more than one sylow $2$-subgroups or more than one sylow $3$-subgroups.
$|G|=2^23^2.$ If $G$ has a unique Sylow $2$-subgroup $H$ then $H\lhd G$ and $O(G/H)=3^2.$ So $G/H$ is abelian. I don't know what to do next?
Please help me !!