Seven chits are numbered $1$ to $7$. Three are drawn one by one with replacements. The probability that the least number on any selected chit is $5$, is
My teacher says that the favourable outcomes are $5, 6, 7$, so the probability is $\left( \frac 3 7 \right)^3$.
But I think that this also includes cases like $(6, 6, 7)$. So I'm getting the probability of $\frac{3^3-2^3}{7^3}$, after excluding the cases of only $6$'s and $7$'s.
Which of these is the correct interpretation of the question? Thanks.