Deriving Kinematics Equation without Calculus / First Principle 
How do I derive the Kinematics equation $v=v_0+at$ from the equation $x = x_0+v_0t+\frac12at^2$?

This is how I have tried :
$$x - x_0=v_0t+\frac12at^2$$
$$\Delta x= t(v_0+\frac12at)$$
$$\dfrac{\Delta x}{t}= v_0+\frac12at$$
$$v = v_0+at$$
I'm stuck with the $\frac12$. How to get rid of that ? Please Help !
 A: Hmm how about this:
$$x(t+\Delta t)=x_0 + v_0( t + \Delta t)+ \frac12a(t+ \Delta t)^2$$
We know that at each and every point the velocity is different since there is an acceleration, but let's take a small time interval $(t,t+\Delta t)$, then change in position for this interval of time is given as::
$$ x(t + \Delta t) - x(t) = v_0 \Delta t + \frac12 a( 2t \Delta t + \Delta t^2)$$
Now, if to find velocity we divide by the time gap:
$$ v(t) = \frac{x( t+ \Delta t) - x(t)}{\Delta t} = v_0 + \frac12 a( 2t+ \Delta t)$$
But remember, each point has a different velocity due to acceleration, so to get the best idea for rate of change of position for the motion at a point, let us take the time gap to be really small then we find that all terms of $\Delta t$ on RHS die off:
$$ v(t) = v_0 + at$$
And that's it.
A: It is entirely possible to derive the equation without calculus, here is how:
Firstly, you are wrong in substituting $\Delta x/t$ with $v$. The ratio $\Delta x/t$ is, the average velocity, and not the velocity at time $t$. Since this is a case of uniform acceleration, we have
$$\frac{\Delta x}{t}=v_{\text{avg}}=\dfrac{v+v_0}{2}$$
implying
$$\dfrac v2+\dfrac{v_0}{2}=v_0+\dfrac12at$$
Simplifying will give you the required equation.
Hope this helps. Ask anything if not clear :)
A: To derive it the way you want you would need some basic calculus (derivatives), but the equation $v = v_{0} + at$ can be understood without that. The definition of acceleration ($a$) is change in velocity ($v$) per second. This equation only works when the acceleration is constant so the change in velocity over a period of ($t$) seconds is $at$ (literally change per second times number of seconds). Then it is clear that the equation says "final velocity = initial velocity + change in velocity".
If you want to get the basics of calculus, here is a great series on it:
https://www.youtube.com/playlist?list=PLZHQObOWTQDMsr9K-rj53DwVRMYO3t5Yr
A: $$ x = v_0t + ½at²$$
$$\frac{dx}{dt}=v_0+\frac{2}{2}at$$ ~ Differentiate respect to time.
$$v=v_0+at$$
You can learn calculus from here. I like these tutorial.
