# Derivative of integral representation of Greens Function

I am interested in taking the differentiation of an integral representation containing the fundamental solution of the heat equation, hence the Greens function.

The equation of interest I want to differentiate is given as:

$$f(x)=\int_0^t \rho(\tau) K(-x,t,y,\tau)d \tau,$$

with $$K(-x,t,y,\tau)=\frac{1}{2\sqrt{\pi(t-\tau)}}e^{-\frac{(-x-y)^2}{4(t-\tau)}}=\frac{1}{2\sqrt{\pi(t-\tau)}}e^{-\frac{(x+y)^2}{4(t-\tau)}}.$$

I want to evaluate the spatial derivative of this equation at the boundary $$x=s(t)$$, hence I am interested in $$\frac{\partial f(x)}{\partial x}(x=s(t))$$.

I know of a Lemma [(2.1) on page 501 of [Fr 1959] A. Friedman, Free boundary problems for parabolic equations I. Melting of solids. J. Math. Mech. 8 (1959), 499-517.] for evaluating derivatives of integral representations containing $$K(x,t,y,\tau)=\frac{1}{2\sqrt{\pi(t-\tau)}}e^{-\frac{(x-y)^2}{4(t-\tau)}}$$, which states that I cannot simply differentiate the right-hand-side in respect of $$x$$ at that boundary.

$$\lim\limits_{x \rightarrow s(t)-0}\int_0^t {\frac{\partial}{\partial x}\rho(\tau)K(x,t,s(\tau),\tau)d \tau} = \frac{1}{2} \rho(t)+\int_0^t \rho(\tau)\Bigr[\frac{\partial}{\partial x}K(x,t,s(\tau),\tau) \Bigr](x=s(t)) d \tau$$
$$\int_0^t {\frac{\partial}{\partial x}\rho(\tau)K(-x,t,y,\tau)d \tau}$$ and evaluate it at $$x=s(t)$$?
Are there similar rules for terms containing $$K(-x,t,y,\tau)$$ as for those with $$K(x,t,y,\tau)$$?