Show that if $T:E\times F\rightarrow G$ is a non-identically zero bilinear map, then there's two sequences with this property [closed]

Question

Let $E,F,G$ be normed spaces, and let $T:E\times F\rightarrow G$ be a non-identically zero bilinear map, then there are two sequences $(u_n)_{n\in\mathbb{N}}$ and $(v_n)_{n\in\mathbb{N}}$ in $E\times F$, with $$ \lim_{n\to \infty}\|u_n-v_n\|_{E\times F} = 0 $$ and $$ \lim_{n\to \infty}\|T(u_n)-T(v_n)\|_{G} > 0. $$

We are using the product norm: $$ \|⋅\|_{ExF} = \max\{\|⋅\|_{E},\|⋅\|_{F}\}. $$

Answer 1

If $T(e,f)\ne0$ then define $u_n = n (e,f)$, $v_n=(n+\frac1n)(e,f)$.

This basically reduces everything to $E=F=G=\mathbb R$: the claim follows since $\|u_n-v_n\| = \frac1n\|(e,f)\|$ and $\|T(u_n)-T(v_n)\|=\|T(e,f)\|\cdot (2 + \frac1{n^2})$.