I'm struggling with this question and was wondering if anyone could help. Thanks!
When a polynomial $P(x)$ is divided by $(x-2)(x+4)$, the remainder is $(3x-5)$. What is the remainder when $P(x)$ is divided by $(x-2)$?
Any help would be greatly appreciated!
Edit: This is my attempt so far:
I have expanded $(x-2)(x+4)$ which gives me $x^2+2x-8$ but for remainder theorem it is $f(x-a)$ remainder so it's a bit different, hence I don't know how to proceed.
I also thought of doing $P(x) = (x^2+2x-8)Q(x) + 3x-5$ but don't know where to go from here.