Let $f, g \colon \mathbb{R} \to \mathbb{R}$ be functions such that f is bounded, i.e. $\exists M \in \mathbb{R}^+ \colon \vert f(x) \vert \leq M$ and $\lim \limits_{x \to x_0} g(x) = 0$.
I need to proof that $\lim \limits_{x \to x_0} f(x) g(x) = 0$ using the $\left( \epsilon, \delta \right)$ definition of limit.
This is what I've got so far ($h(x) := f(x)g(x)$):
$\forall \epsilon > 0, \exists \delta > 0, \forall x \in \mathrm{Dom}(h), 0 < \vert x - x_0 \vert < \delta \implies \vert h(x) - 0 \vert = \vert h(x) \vert< \epsilon$.
Using the definition of $h(x)$ and the fact that $f$ is bounded I got:
$\vert h(x) \vert = \vert f(x) g(x) \vert = \vert f(x) \vert \vert g(x) \vert \leq M \vert g(x) \vert = \epsilon$.
I'm stuck there.
Thanks!