# Is it true that $\text{Ext}(A,\Bbb Z)=\text{Ext}(A_{tor},\Bbb Z)$ for any abelian group $A$?

Is it true that $$\text{Ext}(A,\Bbb Z)=\text{Ext}(A_{tor},\Bbb Z)$$ for any abelian group $$A$$? Obviously this is true when $$A$$ is finitely generated, since $$\text{Ext}(G,\Bbb Z)=0$$ if $$G$$ is free. But I'm curious that whether or not this is true in the general case.

Take $$A = \mathbb Q$$, since it is torsion free we have $$\mathsf{Ext}(\mathbb Q_{\mathsf{tors}}, \mathbb Z) = 0$$, but $$\mathsf{Ext}(\mathbb Q,\mathbb Z) \neq 0$$. See here.