# Prove that the set of all infinite subsets of $\mathbb{Q}$ has cardinality $\mathfrak{c}$ [closed]

How to prove the set of all infinite subsets of $$\mathbb{Q} = \mathfrak{c}$$, if you first prove that the cardinality of the set of all finite subsets of $$\mathbb{Q}$$ is $$\aleph_{0}$$.

I know how to prove the finite subset of $$\mathbb{Q}$$ is $$\aleph_{0}$$ but hard to reach this problem

New contributor
RLOUIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
• Do you know that the set of all subsets of $\Bbb N$ has cardinality $\mathfrak{c}$? – Brian M. Scott 2 days ago
• I know the cardinality of the set of all real numbers is 2^N0 – RLOUIS 2 days ago
• Is N you way of writing $\aleph$? – Hagen von Eitzen 2 days ago
• Yes, N is ℵ. I just write n simply. – RLOUIS 2 days ago
• Ok I got your point. Thank you for your help. – RLOUIS 2 days ago