I'd like to understand the asymptotics of the q-Pochhammer symbol $(a;q)_\infty$ as $q \to 1^-$ with $a$ complex, where
$$(a;q)_\infty = \prod_{n = 0}^\infty (1- aq^n).$$
More specifically, I'm actually just interested in the limiting behavior as $a$ approaches an arbitrary point on the unit circle in the complex plane: $(q^x e^{i \theta}; q)_\infty$ as $q \to 1^-$, with $x$ and $\theta$ real. I managed to find a partial answer in this paper, which in theorem 3.2 gives the asymptotic expansion
$$(q^x; q)_\infty = \frac{\sqrt{2\pi}}{\Gamma(x)}\left(\ln\frac{1}{q}\right)^{\frac{1}{2}-x} \prod_{k = 0, k \neq 1}^\infty \exp\left[\frac{\zeta(2-k)}{k!} B_k(x) (\ln q)^{k-1}\right]$$
for $x > 0$, where $\zeta(2-k)$ is the Riemann zeta function and $B_k(x)$ are Bernoulli polynomials. This is just the $\theta = 0$, $x > 0$ version of what I'm looking for. Doing some numerical checks, it seems that this expansion is still valid when extended to complex $x$ (at least in some neighborhood of $x = 0$, which is all I've checked), but this generalization isn't sufficient to get the expansion I want: in the expansion above, the argument $a = q^x$ always approaches 1 as $q \to 1$ even for complex $x$, whereas I want $a = q^x e^{i\theta}$ to approach an arbitrary point on the unit circle.
Is there some other expansion that applies in the regime I'm interested in? Or perhaps is there a way to modify the above expansion to work for general $\theta$?