We have a bin with 9 balls, 4 blue balls and 5 red balls. In how many ways can we pick three (3) balls so that we have a ball of each color?
We have a deck of 52 playing cards, 13 of each of the four suits. In how many ways can we pick five (5) cards so that there are at most two suits represented among the five cards? (As e.g. in three hearts and two clubs, but no spades and no diamonds.)
For the first question, I got 140 as my answer. I divided it into two cases: 1R 2B or 1B 2R, but i don't know if I did it correctly.
2((5C1)(4C2)) + 2((5C2)(4C1)) = 140
I am just getting started with this topic, can anyone help me with these questions, thanks.