# What information do I get about the linear relations between a Matrix' lines from its rank?

So, let's say I have a 4x2 matrix with a positive rank.

The maximum rank of the matrix is 2, and if the rank of the matrix is 1 I then know that one of the lines in the matrix is a scalar times the other line of the matrix.

Now, let's say I have a 6x3 matrix with a positive rank. The maximum rank of the matrix is 3, but I struggle to understand the difference between when the rank is 1 and when the rank is 2. I understand that a matrix' rank is the number of non-zero rows in its row echelon matrix, but I struggle to understand what it tells me.

Let's say I have rank 2. Does it mean that I get a linear combination of 2 lines that provides the 3rd? If so, what does rank 1 get you?

I really hope the question is coherent. Thank you and have a blessed day.

• Welcome to MSE. Please don't assign tags if you don't know what they mean, or how they relate to the problem. This has nothing to do with either manifolds or jacobians. Mar 17, 2021 at 21:22
• well, I had 2 tags left so I added those because that's the math I was doing while I realized that I have a rank problem mb Mar 17, 2021 at 21:25
• You may assign up to $5$ tags, but you don't have to use $5$. I see few questions with more than $2$. If a user is watching the tag "manifolds" for example, he will get a notification that a post has been made with that tag, and so the post should really be something about manifolds. Mar 17, 2021 at 21:30

In the spirit of your question however, the rank is the maximum number of linearly independent rows (or columns). So you are correct in your example about the meaning of rank $$2$$. If the rank were $$1$$, it would mean that there is some row, such that each of the other rows is a scalar multiple of it. We can choose any nonzero row as the distinguished row. In general, if there rank is $$r$$ there are $$r$$ rows, such that every row of the matrix is a linear combination of those $$r$$ rows, and this isn't true for any number less than $$r$$.