The problem is as follows:
A merchant has a kiosk and has one bag with $6.8$ kilograms of corn and a two pan scale and three weights. One measures $5$ kilograms, the other $2$ kilograms, and the other $1$ kilogram. In how many weighing trials at minimum could he serve an order of $2700$ grams of corn?
The choices given are:
- $4$ trials
- $3$ trials
- $1$ trial
- $2$ trials
I'm not sure exactly how to get to the right combination for this problem. It would be very nice if the answer could include the steps in a logical and very detailed way so I can understand.
To my best of ability I thought that I could arrange the weights as follows:
$5$, $2$, $1$, $6.8$
To get $2.7$ from these numbers is somewhat convoluted to me. Thus I need some help. What can I do?
The thing is either method which I've tried from subtracting this amount from $6.8$ does give me more than what I need, thus I am going in circles.