$1+1+1+1+1+1+1+1+1+1+1+1 \cdot 0+1 = 12$ or $1$? Does the expression $1+1+1+1+1+1+1+1+1+1+1+1 \cdot 0+1$ equal $1$ or $12$ ?
I thought it would be 12 this as per pemdas rule:
$$(1+1+1+1+1+1+1+1+1+1+1+1)\cdot (0+1) = 12 \cdot 1 = 12$$
Wanted to confirm the right answer from you guys. Thanks for your help.
 A: Multiplication takes priority over addition, so this

$1+1+1+1+1+1+1+1+1+1+1+1\times0+1$

becomes:

$1+1+1+1+1+1+1+1+1+1+1+0+1$

Now add everything which gives you 12.
A: \begin{align*}
& 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + (1\times0) + 1\\ 
= &1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 0 + 1\\ 
= &12
\end{align*}
A: If you type $1+1+1+1+1+1+1+1+1+1+1+1⋅0+1$ into most pocket calculators you will get the answer $1$. This is because the calculator applies the next operation to the result of the previous one, effectively computing$$(1+1+1+1+1+1+1+1+1+1+1+1)⋅0+1=0+1=1$$
When using a calculator you have to respect the logic of the machine. When writing mathematics you need to be aware of the standard conventions for brackets, which give the answer $12$ in this case. I suspect that the confusion arises because the two are not the same. Understanding why will help you to make better use of a calculator and to write correct mathematical equations.
A: Your answer of $12$ is numerically correct, but you’ve applied the precedence rules incorrectly. In the absence of parentheses multiplication is done before addition, so 
$$1+1+1+1+1+1+1+1+1+1+1+1\cdot 0+1$$
is to be evaluated as
$$1+1+1+1+1+1+1+1+1+1+1+(1\cdot 0)+1\;,$$
not as
$$(1+1+1+1+1+1+1+1+1+1+1+1)\cdot(0+1)\;.$$
Since $1\cdot0=0$, this simplifies to
$$1+1+1+1+1+1+1+1+1+1+1+0+1=12\;.$$
A: $1+1+1+1+1+1+1+1+1+1+1+1 \cdot 0+1$
since priority of multiplication $\times$ or $\cdot$ is greater than addition $+$ so expression will be:
$1+1+1+1+1+1+1+1+1+1+1+0+1\implies 12$
This is the order of operation:
$1$ B:- Brackets first
$2$ O:- Orders (i.e. Powers and Square Roots, etc.)
$3$ DM:- Division and Multiplication (left-to-right)
$4$ AS:- Addition and Subtraction (left-to-right)
I think this will helpful :
http://www.magicalmaths.org/bodmas-starter-5-5-5-5-5-5-5-5-x-0-i-bet-more-people-will-answer-it-wrongp-give-a-try/
A: $1+1+1+1+1+1+1+1+1+1+1+1⋅0+1$
So, $1*0=0$ witch means that we Are Left with
$1+1+1+1+1+1+1+1+1+1+1+1(+0)$ witch is $12$
