1
$\begingroup$

Solve the following system of equations: $\left\{\begin{matrix} x^3(1-x)+y^3(1-y)=12xy+18\\ \left | 3x-2y+10 \right |+\left | 2x-3y \right |=10 \end{matrix}\right.$

$\endgroup$

closed as too localized by Gerry Myerson, Amzoti, Lord_Farin, Micah, Asaf Karagila May 28 '13 at 13:20

This question is unlikely to help any future visitors; it is only relevant to a small geographic area, a specific moment in time, or an extraordinarily narrow situation that is not generally applicable to the worldwide audience of the internet. For help making this question more broadly applicable, visit the help center. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 4
    $\begingroup$ No source, no motivation, no effort beyond cut'n'paste --- not good for this website. $\endgroup$ – Gerry Myerson May 28 '13 at 12:26
  • $\begingroup$ yeah same from me.show some effort ,show steps where you've stuck. $\endgroup$ – iostream007 May 28 '13 at 12:29
3
$\begingroup$

Perhaps asking Mathematica(WolframAlpha gives the answer as well) to solve it:

Solve[{x^3 (1 - x) + y^3 (1 - y) == 12 x y + 18, 
       Abs[3 x - 2 y + 10] + Abs[2 x - 3 y] == 10}, {x, y}, Reals]

immediately gives:

$$\left\{\left\{x\to -\sqrt{3},y\to \sqrt{3}\right\}\right\}$$

And there is this nice plot of the two curves:

enter image description here

P.S. I will probably(if I find a reason to) add an analytic answer later.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.