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I am recently learning the how to use the various methods to solve recurrences. So far I have acquainted myself with the Master's Theorem and Substitution method. One method I just can't seem to understand is the following question which needs to be solved by characteristic equation:

$$ T(n) = 2T(n/3) + 1,T(1) = 1$$

I watched certain tutorials and readings and I imagine I needed to derive some sort of degree and simultaneous equation out of this?

How do I do it in this case?

Sorry for being amateur at this.

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  • $\begingroup$ Are you sure it needs to be solved by characteristic equation only? $\endgroup$ – Beyond Infinity 2 days ago
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Write $n=3^m$ so $T(3^m)=2T(3^{m-1})+1$.

Then let $T(3^m)=u(m)$ so $u(m)=2u(m-1)+1$.

You should be able to solve this.

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