# Ant Slipping classical mechanics

Suppose we have on a horizontal timetable

$$m\textbf{a}_{rot}=\textbf{F}-\textbf{F}_{corialis}-\textbf{F}_{centrifugal}$$

where $$\textbf{a}_{rot}$$ is the acceleration in a rotating frame. Suppose an ant on the turntable walks from the centre at constant speed. Suppose an ant slips an experiences a horizontal force exceeding a value $$F$$.

Explain why $$F^2=|\textbf{F}_{corialis}|^2+|\textbf{F}_{centrifugal}|^2$$

I have no idea why the above holds. May someone elaborate

• This is a gentle reminder to consider accepting an answer if your question has been resolved. – Sal Feb 27 at 13:42