Suppose we have on a horizontal timetable


where $\textbf{a}_{rot}$ is the acceleration in a rotating frame. Suppose an ant on the turntable walks from the centre at constant speed. Suppose an ant slips an experiences a horizontal force exceeding a value $F$.

Explain why $F^2=|\textbf{F}_{corialis}|^2+|\textbf{F}_{centrifugal}|^2$

I have no idea why the above holds. May someone elaborate

  • $\begingroup$ This is a gentle reminder to consider accepting an answer if your question has been resolved. $\endgroup$ – Sal Feb 27 at 13:42

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