I know circular arrangement of $n$ different objects can be done is $(n-1)!$ ways.
For example :- I arranged $7$ objects in circle
This can be done in $720$ ways (using $6!$)
$1$) Can I also do this problem as below ??
I made circular arrangement of $6$ objects in $5!$ ways.
Then I selected $1$ gap out of $5$ gaps between objects to put $7$th object
$2$) If yes
then It will give answer = $5!$ $5$
=$600$ (not $720$)
($1$) it is possible
But gap should 6 (as there are 6 gaps if we arrange them in linear way)
($2$) we have to use different formula .
like $5!$ 6
But I am not sure