Confusion between operation and relation: Clarification needed I'm doing some old exams and found following question:

Set $S={{1,2,3}}$ is given. Provide an
  example of binary operation in set S,
  binary relation in set S and a
  function $f:S\rightarrow R$.

So, I'm thinking about $+_4$ as operation, but wouldn't it be a relation too? I can take ordered pair from $S$ and for every ordered pair associate an element form $S$ with every pair.
For the third part, I'm thinking about $y=x*1.25$ or something similar, but that part isn't so problematic for me. 
I did read the Wikipedia articles, but the difference between operations  and relations isn't clear to me.
 A: A binary operation is a function from $S\times S \to S$ such as addition, multiplication or anything really.
A binary relation is just a subset of $S^2$, that is not necessarily a function and it doesn't have to include all the elements of $S$ in one way or another.
A function $f\colon S\to R$ is a relation, this time it's a subset of $S\times R$ however it satisfies a certain property, if you take some $s \in S$ then there is only a unique ordered pair with $s$ in it, so if you have $\langle s,r_1\rangle$ as well $\langle s,r_2\rangle$ then you can say that $r_1 = r_2$.
A: BINARY OPERATION: A binary operation is a rule that combines the elements or any mathematical objects of the same kind and produces the third element or object of that kind.
BINARY RELATION:  A binary relation on a set $A$ is a collection of ordered pair of elements  of $A$. Or, simply a subset of Cartesian  product, $A\times A$. 
FUNCTION: A function is a particular type of relation  which maps every point in a domain to a unique point in the range.
