# Is there a way to simplify $2^{2^{n-1}}$?

A question from a math noob...

Is there a way to simplify the following? $$2^{2^{n-1}}$$

• In general, exponents in a "tower" like that are hard to simplify. Maybe you could try $$2^{2^{n - 1}} = 2^{2^{n}/2} = \sqrt{2}^{2^{n}}$$ – Joshua Wang Feb 1 at 3:23
Not really. $$2^{2^{n-1}}$$.
If it’s part of an equation you can take the log $$2^{n-1} log 2$$. Another log and you get $$(n-1)log 2 + log log 2$$.