Strategy of a game Alice and Bob are playing a game. They write down the integers between $1$ and $100$ (inclusive). First, Alice chooses a number she likes and deletes it, and then Bob chooses to delete another number among the divisors and multiples of the one Alice deleted. Then Alice repeats what Bob has done, choosing another number among the divisors and multiples of the one Bob deleted. The game continues until one of them has no choices and the other wins.
For example, Alice chooses $94$. Bob chooses $47$. The only choice left for Alice now is $1$. And then Bob chooses $97$ to win the game.
To make the question interesting, we add the restriction on Alice that she can only begin with an even number.
The question is: Does Alice have a winning strategy?
It can be interpreted as a graph. The graph has $100$ vertices and has edges between every divisor-multiple pair. When a point is deleted, if every point with an edge to the deleted point has no winning strategy for Alice, then the deleted point has a winning strategy for Bob.   But I can't run the program on my PC. Maybe there is a wiser strategy?
 A: If at any time Bob chooses $1$ then Alice chooses $97$ and wins. So in the following I will ignore this choice for Bob.
Alice wins by playing $62$. There are two possibilities.
Bob chooses $31$
Alice now forces the following sequence where Alice's choices are asterisked. She always chooses a product of two primes greater than $50$ where one of the primes has already been used and so Bob has no choice (other than $1$).
$*93*,3,*51*,17,*85*,5,*95*,19,*57*$ and now $1$ is forced.
Bob chooses $2$
Alice now forces the following sequence.
$*58*,29,*87*,3,*51*$ and now as in the above sequence.
A: EDIT : Oops, misread the question. This would be too easy.

Alice chooses a prime number bigger than 50 (Grothendick would say 57)
; then Bob's only choice is 1, and then Alice can choose any number
again. She picks a new prime number bigger than 50, and Bob is stuck.

For your program, take care : the strategy depends on which numbers have already been played, so you can't decide whether a starting point is winning by analysing the other starting points' results.
