The question is:
Given that: $$7\sin^2(x) + \sin(x)\cos(x) = 6$$ Show that: $$\tan^2(x) + \tan(x) - 6 = 0$$
I don't know if there's a proof I'm missing when trying to complete this. I've tried both the $\sin(x)/\cos(x) = \tan(x)$ and the $\sin^2(x) + \cos^2(x) = 1$, and neither of them have got me closer to the answer.
Any help would be appreciated because it's driving me insane not knowing how to do this. I'm not sure if I'm missing something in the proofs I've been using or if I need a different one entirely.