# If a polyomino tiles the plane, is there necessarily a larger tiling polyomino formed by two copies of it?

Say that we have a polyomino $$P$$ which tiles the plane. In may cases, it can do so by forming a two-tile "patch" which tiles the plane. For instance, with the T pentomino:

Is there always a way to take the disjoint union of two congruent copies of $$P$$ to form a polyomino $$Q$$ which also tiles the plane?

This feels intuitively false to me - it doesn't feel like there should be any reason for it to hold, even in the case of periodic tilings (once the period is large enough, anyway). However, it holds for every polyomino on up to $$9$$ cells, so I've struggled to locate a counterexample.

Can anyone provide a counterexample to this claim (or, if my intuition is completely off, a proof)?

Note that one obstacle is the Conway criterion; any tile which satisfies it will generate such a $$Q$$.

This should be a much easier-to-disprove question than this one, which would require the discovery of a connected aperiodic prototile at a minimum.

If you want to know how I arrived at this guess: I thought that a counterexample must tile the plane in a slightly complicated way, so I picked a 3-anisohedral tile and checked if it worked, and so it did. I did not thoroughly check other examples, but a few quick checks makes me think $$k$$-anisohedral tiles may be fertile ground for counter-examples. Here is a site that gives the sets of $$k$$-anisohedral polyomines.