# What does this mean and how to solve it?

The equation described on the chord $$3x + y + 5 = 0$$ of the circle $$x^2 + y^2 = 16$$ as a diameter, is:

(A) $$x^2 + y^2 + 3x + y - 2 = 0$$

(B) $$x^2 + y^2 + 3x + y - 22 = 0$$

(C) $$x^2 + y^2 + 3x + y + 1 = 0$$

(D) $$x^2 +y ^2 + 3x +y - 11 = 0$$

Given line $$3x+y+5=0$$ and circle $$x^2+y^2=16$$ call $$A$$ and $$B$$ their intersection points. Find the equation of the circle having $$AB$$ as diameter.