# Let $a = \frac{1 + \sqrt{2009}}{2}$ . Find the value of $(a^3 - 503a - 500)^5$ .

Let $$a = \frac{1 + \sqrt{2009}}{2}$$ . Find the value of $$(a^3 - 503a - 500)^5$$ .

What I Tried: We have :- $$(a^3 - 503a - 500)^5 = [a(a^2 - 3) - 500(a - 1)]^5$$ $$= \Bigg(\Bigg[\frac{1 + \sqrt{2009}}{2}\Bigg]\Bigg[\frac{1009 + \sqrt{2009}}{2}\Bigg] - 500\Bigg[\frac{\sqrt{2009} - 1}{2}\Bigg]\Bigg)^5$$ $$= \Bigg[\Bigg(\frac{1010\sqrt{2009} + 3018}{2}\Bigg)\Bigg] - 250(\sqrt{2009} - 1)\Bigg]^5$$ $$=(505\sqrt{2009} + 1509 - 250\sqrt{2009} - 250)^5$$ $$= (250\sqrt{2009} - 1259)^5$$

However, the answer given is $$32$$, so there could have been more simplifications.
As a question, where did I go wrong? Also can anyone give me some simpler way of solving this?

• In the first expression in your attempt, it should be $a + 1$ instead of $a-1$. Commented Jan 4, 2021 at 7:37
• Oh ok, got it. I will check again. Commented Jan 4, 2021 at 7:39
• @MathLover any other typos? That was a typo but the answer I am getting in the end $(255\sqrt{2009} - 759)^5$ , still not complete. Commented Jan 4, 2021 at 7:44
• No I think it simplifies to $32$ Commented Jan 4, 2021 at 7:51

$$a$$ is a root of a quadratic equation with roots $$\frac{1 \pm \sqrt{2009}}{2}$$ That is, $$a$$ satisfies the following equation: $$x^2 - x - 502 = 0 \tag 1$$ Using this, we observe \begin{align}(a^3 - 503a - 500)^5 &= (a(\color{red}{a^2})-503a-500)^5 \\&\overset 1= (a(\color{red}{a+502})-503a-500)^5 \\&= (\color{blue}{a^2-a}-500)^5 \\&\overset 1= (\color{blue}{502} - 500)^5 \\&= 32 \end{align}

Let $$a = \frac{1 + \sqrt{2009}}{2}$$ . Find the value of $$(a^3 - 503a - 500)^5$$ .

I see no reason for elegance. Since one of the factors in the numerator is $$1$$, computing $$a^3$$ is is straightforward.

$$a^3 = \left(\frac{1}{8}\right) \times \left[ 1 + 3\sqrt{2009} + 3(2009) + 2009\sqrt{2009} \right]$$ $$=~ \left(\frac{1}{8}\right) \times \left[6028 + 2012\sqrt{2009}\right] ~=~ \frac{1507 + 503\sqrt{2009}}{2}.$$

Therefore,

$$(a^3 - 503a - 500)$$

$$=~ \frac{1507 + 503\sqrt{2009}}{2} ~-~ \frac{503 + 503\sqrt{2009}}{2} - \frac{1000}{2} ~=~ \frac{4}{2} \implies$$

$$(a^3 - 503a - 500)^5 = 2^5 = 32.$$

$$a = \frac{1 + \sqrt{2009}}{2}$$
$$a^2 - 3 = \frac{999 + \sqrt{2009}}{2}$$
$$a (a^2 - 3) = 752 + 250 \sqrt {2009}$$
$$500 (a + 1) = 250 ( \sqrt {2009} + 3)$$
$$a(a^2-3) - 500(a+1) = 2$$
So $$(a^3 - 503a - 500)^5 = 32$$