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how to solve $$x^2y"-2x(1-x)y'+2(x+1)y=x^3$$ by method of variation of parameters. how do you find solution of the above equation? iam familiar with method of variation of parameters but dont know how to find $y_1$ and $y_2.$ please help.

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You might first need to set an interval for $x$, as the equation degenerates as $x\rightarrow 0$.

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