The vertex-first parallel projection of the tesseract into three-dimensional space has a rhombic dodecahedral envelope. What is the four-dimensional projection of the five-cube? By analogy, its envelope should be a four-dimensional polytope that dissects into 5 congruent "rhombic" tesseracts in two possible ways. What's the name of this object?
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1$\begingroup$ Related: math.stackexchange.com/questions/255112/name-this-polytope $\endgroup$– Ravi FernandoCommented Dec 20, 2020 at 0:19
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$\begingroup$ @RaviFernando Thx, this is basically what I was asking $\endgroup$– Bipolar MindsCommented Dec 20, 2020 at 11:38
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