0
$\begingroup$

Yesterday I asked this question seems not clear. So, I am writing new question with mathematical terms only.

Here is some points about shapes I used:

  • Square: Rectangle that all angles are 90° & all sides are equal length. So, consider Square also a Rectangle.
  • Triangle: I used an equilateral triangle is a triangle in which all three sides have the same length.
  • Polygon: A finite number of straight line segments connected to form a closed.

So, Here after I use the term Polygon to describe triangle & rectangle shapes when it's required to mention consider this shape as polygone. Becuase, I used triangle (regular polygon) to simplfy the work to find out the formula.

Variables used in this problem:

  • b = Border width

Bounds of Outer Rectangle (r) that enclosing the polygon(p):

  • x = Origin x
  • y = Origin y
  • w = Width
  • h = Height

So, If r = (x,y,w,h) then, Bounds of Inner Rectangle that encloses the inner polygon(p1) (r1) = (x1,y1,w1,h1)

Here, inner polygon = Polygon by subtracting the border width.

What is my final goal:

I should able to calculate inner rectangle boundary of any polygon like below image, I have angles, outer rectangle bounds & border width. The problem is to find out the inner rectangle bounds across to the outer rectangle based on the polygon at that enclosed by inner rectangle.

enter image description here

Problem 1:

Consider a Polygon(p) as a shape of rectangle(r) which has width(w) is 100 & height(h) is 100. The border width of the polygon is 10. The what is the inner boundary of the rectangle that encloses the inner polygon?

Note: I solved it by mind calculation(I didn't took angles in the calculation). But we can't apply this same formula for triangle. So, this is not solution for my problem.

enter image description here

Problem 2:

Consider the polygon (don't consider regulard) with three edges and three vertices & all angles are equal in measure.

If the rectangle(r) boundary is zero & size(w,h) is (100,87) that encloses the polygon(p) along with polygon border width as 10, then

What is the bounds of the inner rectangle(r2) that encloses the inner polygon(p2) ?

enter image description here

Hope I clearly explained the problem. If anything I am missed then please let me know. Thanks in advance.

$\endgroup$
0
0
$\begingroup$

RectangleBounds

Let us denote width and height of the inner rectangle as $w_\mathrm{in}$ and $h_\mathrm{in}$ respectively. Then, we have, $$w_\mathrm{in} = w-2\sqrt{3}b. \qquad\mathrm{and}\qquad h_\mathrm{in} = h\space–\space3b.$$

Using these results, we can easily derive the coordinates of the four corners of the sought rectangle $P$, $Q$, $R$, and $S$ as given in the diagram.

Frankly, I am not sure whether these are the results you were looking for. If you have doubts you can always comment on this answer no holds barred.

$\endgroup$
4
  • $\begingroup$ Thank you so much!, Yes this is the answer exactly I am looking for solving triangle problem. I will check & let you know If an doubts. Thanks! $\endgroup$ – Noob Dec 17 '20 at 17:52
  • $\begingroup$ These are the result when applying formula P, Win, Hin and got result Frame:(0.0, 0.0, 100.0, 87.0) Win: 89.04554884989668 Hin: 57.0 Inner Rect Origin: (5.477225575051661, 10.0) and This is the result I got ploted [imgur.com/CRaBpPI]. Here you can see full variable border width: [imgur.com/2LvBVhQ], This is the calculation screenshot: [imgur.com/sr1dZhp], Am I missed anything wrong? $\endgroup$ – Noob Dec 18 '20 at 4:34
  • $\begingroup$ According to my calculations, all your values, except those of $P$ and $w_{in}$, are correct. The correct values of $w_{in}$ is 65.3589838486 and that of $P$ is $\left(17.320508075689,10\right)$. $\endgroup$ – YNK Dec 18 '20 at 8:55
  • $\begingroup$ I was first unable to view any of your diagrams, because their link-embedding was faulty. Since this is a comment, you cannot edit it to correct the fault. But, you can delete your comment and post a new comment with right embedding of those three links. However, I manage to view your calculation screenshot. The formula you used to calculate $W_{in}$ is wrong. The correct statement is $\mathrm{\mathbf{\color{red}{let\space win\space =\space rect.width\space -\space 2*sqrt(3)*borderWidth}}}$ $\endgroup$ – YNK Dec 18 '20 at 8:58
0
$\begingroup$

Inner triangle is the image of outer triangle under a homothetic transformation centred at the centre of the triangle.

  • The centre of the triangle is located on the altitude, at $1/3$ of its length starting from the base.

  • The ratio $r$ of the homothety can be computed as the ratio of the distances from the centre to the midpoint of the bases: $$ r={{1\over3}{\sqrt3\over2}100-10\over {1\over3}{\sqrt3\over2}100}= 1-{\sqrt3\over 5}. $$

Inner rectangle is then the image of outer rectangle under the same homothety.

$\endgroup$
1
  • $\begingroup$ Thank you very much! I will try your formula & will update $\endgroup$ – Noob Dec 17 '20 at 17:32

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.