5
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Is there a way to solve the following equation algebraically?

$(x+3/5)^{5x-3}=16$

So far, I have figured out a solution to be 7/5. This was solved by comparing the exponential form of 16 but I am not convinced this is the right approach. There is also another solution (negative).

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    $\begingroup$ So What you are saying is that you have solved it for $2^4 = (x+3/5)^{5x-3} $? $\endgroup$
    – ombk
    Nov 24, 2020 at 0:52
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    $\begingroup$ @ombk yes. it allows you to obtain the first solution, 7/5 $\endgroup$
    – azetina
    Nov 24, 2020 at 1:04

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