$$x^2 + xy + xz = 2$$ $$y^2 + yz + xy = 3$$ $$z^2 + zx + yz = 4$$
I tried solving it but i just ended up with $$(x-y)(x+y+z) = -1$$ $$(y-z)(x+y+z) = -1$$ $$(x-z)(x+y+z) = -2$$
I'm not sure what to do. Any hints?
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