I'm solving a homework problem and I need to explicitly show that 2 angles are distinct. The problem is as follows:
Given a circle of radius $4r$ which is tangent to a circle of radius $2r$, take a line parallel to the axis which connects both circle centers that is $r$ distance apart from said axis. We call the $2$ points from the intersection of this secant line with both circles that are furthest apart to be $A$ and $B$, and we call the other pair of points $C$ and $D$. Show that the angle between $A,B$ and the tangency point is greater than the angle between $C,D$ and the tangency point.
It seems fairly obvious that the triangle$\triangle PAB$ contains the smaller triangle $\triangle PDC$, but I don't know how to justify this. I was thinking of explicitly calculating the equations for both circles and the secant line to calculate the coordinates of the points, but it seems like overkill to me. Does anyone know a simple argument I could use to show that $\angle APB \neq \angle CPD$?