This is the same as the comment above.
I often see $\operatorname{Ext}$ when we want the i-th derived functor, that is $\operatorname{Ext}^i$ while $R\operatorname{Hom}$ is more often used as the total derived functor, in other words an object of the derived cateogry (a complex up to quasi-isomorphism). The relationship is thus $\operatorname{Ext}^i=H^i(R\operatorname{Hom})$ (or something similar if instead of the derived category, we have the homotopy category of some model category). I guess some author do not use this choice of notation (I won't even say convention because it isn't), but this is what I see the most often.
I guess, we don't use $\operatorname{Ext}$ for the total derived functor because this notation is more often use for the group of extensions in an abelian category (this is the case for instance in the linked nLab page for the Ext functor), so that we are able to claim that there is a natural isomorphism $\operatorname{Ext}=\operatorname{Ext}^1$.