0
$\begingroup$

In a triangle ABC Let a point X be the point of tangency of the excircle opposite A with side BC. I am trying to prove the point X cannot cannot lie on the nine-point circle of triangle ABC. I proved that there could not be three intersections across side BC, but how can I prove that X can't possibly be a point on side BC that coincides with the midpoint or the other point of intersection of the nine-point circle?

$\endgroup$
0
$\begingroup$

Let the triangle be isosceles and then use Feuerbach's Theorem and Feuerbach's Point to prove the conjecture.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.