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Given a manufacturing line of 4 phases with:

Phase 1 (5s) -> Phase 2 (10s) -> Phase 3 (8s) -> Phase 4 (7s) -> finished

In each phase, there can only be 1 product under working ( maximum capacity of 1). A product must follow this process. Assuming there is no failure in the manufacturing line, calculate the total number of output after time T= 100s and T= n (second)

My attempt: i tried to calculate the interval after the first product is finished which is 7 second. It seems wrong to me and i dont know whether there is better approach

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    $\begingroup$ Let me know if my question is ambiguous. Thanks! $\endgroup$
    – D H
    Commented Oct 5, 2020 at 10:57
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    $\begingroup$ it's better to mention what you tried as well. $\endgroup$
    – reyna
    Commented Oct 5, 2020 at 10:59
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    $\begingroup$ @zaira I have updated my attempt $\endgroup$
    – D H
    Commented Oct 5, 2020 at 11:18
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    $\begingroup$ The way I read this is that a product is manufactured by going through all four phases of production, so the time it takes to manufacture a product would be the sum of the times for each phase. $\endgroup$ Commented Oct 5, 2020 at 11:29
  • $\begingroup$ @N.F.Taussig yes but different products can be worked on simultaneously in different phases $\endgroup$
    – D H
    Commented Oct 5, 2020 at 11:43

1 Answer 1

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Assuming you start the process with nothing in the pipeline, the first item is completed in $30$ seconds; and then every $10$ seconds thereafter, another item is completed.

$\begin{array}{cc|c|c|c|c} &\rm{phase}&1&2&3&4\\ \rm{item}&&&\\ 1&&0-5&5-15&15-23&23-30\\ 2&&5-10&15-25&25-33&33-40\\ 3&&10-15&25-35&35-43&43-50\\ 4&&15-20&35-45&45-53&53-60\\ \vdots&&\vdots&\vdots&\vdots&\vdots& \end{array}$

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    $\begingroup$ Thx, this is amazing $\endgroup$
    – D H
    Commented Oct 5, 2020 at 13:45

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