Can you prove the following claim? The claim is inspired by Harcourt's theorem.
In any rhombus $ABCD$ construct an arbitrary tangent to the incircle of rhombus . Let $n_1,n_2,n_3,n_4$ be a signed distances from vertices $A,B,C,D$ to tangent line respectively, such that distances to a tangent from points on opposite sides are opposite in sign, while those from points on the same side have the same sign. Denote the side length of rhombus by $a$ and the area of rhombus by $A$ , then $a(n_1+n_2+n_3+n_4)=2A$