I encountered this video about number theory question from Swedish Maths Olympiad:
Find all integers $n\geq 8$ such that $n^{\frac{1}{n-7}}$ is also an integer.
The video shows step by step solution. However, I think the question can be solved much easier as the following:
We substitute $x=n-7$ and $n=a^{x}$ to obtain $a^{x}=x+7$. Then quite obviously we find that for $x\geq4$ we have $a<2$ and we only need to evaluate $x=1,2,3$.
Then we find that the only pairs $(a,x)$ are $(8,1)$ and $(3,2)$ i.e. the only solutions are $n=8,9$.
Here is the link of the video: Swedish Mathematics Olympiad