This very straight forward probability question is somehow confusing to me. The box contains $3$ maple donuts, $1$ choc donut, and $2$ glazed. One donut is chosen randomly without replacement and then a second is chosen.
Q1: Create an organized list to represent the sample space for this situation.
In this situation I would think that the order of choice does not matter as you come away with two donuts and the order in which they were chosen does not matter. So, I get $15$ items in the sample space. This is the same number I would get if I were to use the mathematical combination computation of $6$ items taken $2$ at a time. In other words unordered sampling without replacement. My tree matches with the combination of $6$ taken $2$ at a time. $15$ possible ways.
Note: I assume that the $3$ maple donuts are indistinguishable; same with $2$ glazed.
I get stuck when the problem then says, "Use the counting principle to find how many different ways the two donuts can be chosen."
This would seem to indicate that since the first donut can be chosen $6$ different ways and the second donut $5$ different ways I would get $30$. This I know is the answer if I were to chose $2$ donuts from $6$ where order matters (permutation). However, it would seem to me that order does NOT matter in this case.
How can I use the fundamental counting principle in this case to get $15$ ways? Or is the real answer $30$?