0
$\begingroup$

Let a regular curve be defined as $\vec{\gamma}(t):I\to\mathbb{R}^n$. By regular, I mean that $\vec{\gamma}'(t)$ is never the zero vector. Is there an upper bound on its curvature? What is a good way of thinking about this? I really appreciate examples because I'm new to the topic.

$\endgroup$
1
  • 4
    $\begingroup$ No there isn't. Think of circles of smaller and smaller radius. The curvatures get larger and larger $\endgroup$ Sep 23 '20 at 7:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.