In 6/49 lottery 6 numbers are drawn from 49, and jackpot prize is win if ticket matches all 6 numbers. Probability of winning on one play is 1/13983816.
What are the odds of wining jackpot prize in case of:
- Buying X tickets for 1 draw.
- Buying 1 ticket (with the same numbers each time) for X draws in a row.
- Buying 1 ticket (with random numbers each time) for X draws in a row.
Lets assume $X = 8$
- First is trivial: $8/13983816 = 1/1747977$
I'm not sure but think that it will be: $1-(1-1/13983816)^8 = 1/1747977.43835098$
And here I'm confused. Will it be the same as in 2nd case or maybe some other way ?