I was given the following problem:
"Consider the curve defined by $y^2-x^2y=6$ for $y>0$"
"Write an equation for the line tangent to the curve at the point $(1,3)$"
So I thought I could approach it like I would if I were finding the line tangent to a point on a regular curve, thus I evaluated the derivative at the point and plugged that value into the equation for point-slope (and ended up getting an answer of: $y-3=(x-1)$) but I have no clue if this is correct. Any help would be appreciated!