2
$\begingroup$

If $xy$ is constant whenever $z$ is constant,
and $y/z$ is constant whenever $x$ is constant, then show that $xy/z$ is constant.

My work: Write $xy = a$, $y/z = b$. Then

$$xy^2/z = ab, \ \ \ xz = a/b.$$

Any help?

Remark: This shows up in physics when I'm trying to derive the ideal gas equation from Boyle and Charles' laws ($PV =$ constant and $V/T =$ constant).

$\endgroup$
3
  • 1
    $\begingroup$ $xy/z=ab/y$, therefore the assertion will be true if and only if $y$ is constant (or there are some silly zeros here and there), and that's all there is to it. $\endgroup$
    – user239203
    Sep 12, 2020 at 9:27
  • 1
    $\begingroup$ @Gae.S. I see... the textbook mentioned z = constant for first equation and x = constant for second equation. I'll add this to the question... Thank you! $\endgroup$
    – across
    Sep 12, 2020 at 9:29
  • $\begingroup$ @Gae.S. updated the q. please see again $\endgroup$
    – across
    Sep 12, 2020 at 9:30

4 Answers 4

1
$\begingroup$

My interpretation is that $x, y, z$ are independent, but happens that $xy$ depends only on $z$ and $y/z$ depends only on $x$. Then we write

$$\tag{1} xy = f(z), y/z = g(x)$$ for some functions $f, g$.

A priori, $xy/z$ is a function of $3$ variables and we want to show that it is constant. Since

$$ f(z)/z =\frac{xy}{z} = x g(x),$$

One sees that the expression is independent of $x, y$ and $y, z$. Thus it is independent of $x, y, z$ and thus is a constant.

$\endgroup$
3
  • $\begingroup$ Looks neat! so xg(x) is also constant, but how did you conclude it was also a constant? $\endgroup$
    – across
    Sep 12, 2020 at 9:58
  • $\begingroup$ I think I know how you concluded: zg(x) = f(z)/x this implies f(z) = zxg(x). so xg(x) has to be constant for f(z) is a function of z alone. Did I get this right? $\endgroup$
    – across
    Sep 12, 2020 at 10:02
  • $\begingroup$ Ahh ignore my comments. I see now. f(z)/z is clearly independent of x,y. And xg(x) is clearly independent of y,z. Brilliant!!!! $\endgroup$
    – across
    Sep 12, 2020 at 10:06
1
$\begingroup$

If $y=z=\frac1x$, then $xy$ and $\frac yz$ are constants. However,$$\frac{xy}z=x,$$which will not be constant unless $x$ itself is constant.

$\endgroup$
1
$\begingroup$

If $xy$ is constant and $z$ is constant, then $\frac{xy}{z}$ must also be a constant.

This is because if $xy = p$ and $z = q$ where $p, q$ are constant, $\frac{xy}{z} = \frac{p}{q}$, and $\frac{p}{q}$ is constant since $p, q$ are constant.

$\endgroup$
0
$\begingroup$

If $\dfrac {xy}{z}$ is constant and $ xy$ is also constant then $z$ is constant.

If in addition $\dfrac{y}{z} $ is also constant, $y,$ and so $(x,y,z)$ are all constants.

Note from Physics about ideal gas Law proportionalities not exactly.

When T is constant pressure P is proportional to 1/V ( Boyle), and when volume V is constant P is proportional to temperature T (Gay-Lussac) and when P is constant V is proportional to T (Charles).

When combined $\dfrac{PV}{T}$ is a new constant.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .