I'm new to quadratic inequalities. I was trying to solve this following problem -
$$x^2 - 13x + 40 \ge 0 $$ $$(x-5)(x-8) \ge 0 $$
When we consider both of these expressions positive -
$$(x-5) \ge 0$$ and $$(x-8) \ge 0 $$ we get $x \ge 5$ and $x \ge 8$
And I was taught to simplify this as $x \ge 8$. I know this expression also indicates that $x$ is greater than $5$, but it doesn't show that $x$ can be equal to $5$. Or when simplifying expressions with greater than or equal to sign, does equal to doesn't have much significance here.