I try the method of induction on it, but I fail at the last step. I assume that the statement is true for all planes with less than n points. Then if I add one more point to the plane so that it is not collinear to the line with exaclty two points on it, the statement is true for the plane with n points. However, if the new point is added on the line with exactly two points, how can we make sure that there is still a line passing through exactly two points?


This is called the Sylvester-Gallai Theorem. You can find many proofs on the internet, including in the Wikipedia article:


See the following notes for a nice and slick proof: http://web.stanford.edu/~yuvalwig/math/teaching/WhatsThePoint.pdf

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  • $\begingroup$ In Kelly's proof, what does ordinary of a line mean? $\endgroup$ – vegetandy Aug 26 at 12:40
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    $\begingroup$ The terminology is "ordinary line" (rather than "ordinary of a line"). This is defined at the beginning of the article; it's a line that goes through just two points in the collection. $\endgroup$ – halrankard Aug 26 at 12:43
  • $\begingroup$ Thanks, I understand it now, the proof is so clever. $\endgroup$ – vegetandy Aug 26 at 12:45

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