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i have a nasty integral to solve. i tried using the parts method but it just blew off.Can anyone provide a solution much better than what i have done here?.

$$\int x^2 (e^x)^3 \sin x\, \mathrm dx$$

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    $\begingroup$ $(e^x)^3=e^xe^xe^x=e^{3x}$ $\endgroup$ – Adi Dani Apr 30 '13 at 18:11
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Just integrate by parts: $$\int x^2\left(e^x\right)^3\sin x\,\mathrm{d}x=\int u\,\mathrm{d}v\text{ where }u=x^2,\,\mathrm{d}v=e^{3x}\sin x\,\mathrm{d}x$$

Note you may want to tackle $v=\int e^{3x}\sin x\,\mathrm{d}x$ using parts as well, or you could (of course) play with Euler's identity.

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  • $\begingroup$ thanks!! that feels better :D!!! $\endgroup$ – Sri Krishna Apr 30 '13 at 18:12
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Here is another approach. Put $$\Phi(t) = \int e^{3tx}\sin(x)\, dx.$$ Now resolve the integral by integration by parts.

Next, apply Leibnitz's rule for differentiation of the integral to find $\Phi''(t)$ and you are on home base.

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