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If a Continuous function $f(x)$ satisfies $f(x) = f(2x)$, for all real $x$, then does $f(x)$ necessarily have to be constant function? If so, how do you prove it? If not any counter examples?

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2 Answers 2

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For all $x\in\mathbb{R}$ and $n\in\mathbb{Z}$, $f(x)=f(x/2^n)$, so $f(x)=\lim_{n\to\infty}f(x/2^n)=f(0)$ by continuity.

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    $\begingroup$ It even suffices to assume only that $f$ is continuous at $0$ $\endgroup$ Aug 2, 2016 at 7:08
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Counterexample: $f(x)=\sin(\log_a(x))$, select basis $a$ so that $\log_a(2)=2\pi$, that is, $a ^{2\pi}=2$.

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    $\begingroup$ It's not continuous at zero $\endgroup$
    – Quark
    May 24, 2013 at 17:14
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    $\begingroup$ It is continuous everywhere else, which I guess is the best you can do, given the argument above. $\endgroup$
    – Nishant
    Jul 14, 2014 at 21:09

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