Could this integral be estimated with a positive constant? Let $\Omega$ be an opend bounded subset of $\mathbb{R}^n$ and let $p, q$ be two real numbers such that $p, q\geq 1$. Let $(w_n)_n\subset W_0^{1, p}(\Omega)$ and $(z_n)_n\subset W_0^{1, q}(\Omega)$ such that $\exists w\in W_0^{1, p}(\Omega)$ such that
$$ w_n\longrightarrow w \quad \mbox{ in } L^{r}(\Omega) \quad \mbox{ for } \ 1\leq r < p^{\ast}$$
and
$$ w_n\longrightarrow w \quad \mbox{ a.e. in } \Omega.$$
Moreover, fix $k\geq 1$ and consider
$$\Omega_{n, k}:=\left\lbrace x\in\Omega \mid \vert w_n(x), z_n(x)\vert > k\right\rbrace.$$
I would like to show that the integral
$$\int_{\Omega\setminus\Omega_{n, k}} F(x, w_n, z_n) w \vert\nabla z_n\vert^{q} dx$$
can be estimated with a positive constant, i.e. $\exists c\in\mathbb{R}$ such that $\displaystyle\int_{\Omega\setminus\Omega_{n, k}} F(x, w_n, z_n) w \vert\nabla z_n\vert^{q} dx\leq c$.
Here, I assume $F:\Omega\times\Omega\times\mathbb{R}\to\mathbb{R}$ such that
$$ \sup_{\vert (u, v)\vert\leq t} \vert F(\cdot, u, v)\vert\in L^{\infty}(\Omega)$$
for any $t>0$.
Could anyone please help? Thank you in advance!
 A: Since $z_n \in W_{0}^{1, q}$, your only hope on estimating the integral of $|\nabla z_n|^q$ is to put it in $L^1$ and pull out an $L^\infty$ norm of the $F$ term:
$$
\int_{\Omega \setminus \Omega_{n,k}}  |F(x, w_n, z_n)||w||\nabla z_n|^q \, dx \leq \|{z_n}\|_{W^{1 
, q}}\sup_{x \in \Omega \setminus \Omega_{n, k}}  |F(x, w_n(x), z_n(x))||w(x)|.
$$
So to get a uniform bound we'd first need to know that the $z_n$'s are uniformly bounded in $W^{1, q}$, or at least that their gradients are bounded uniformly in $L^q$. Meanwhile the supremum term is finite for each $k$, since $\Omega_{n,k}$ is the set where $w_n, z_n$ are greater than  $k$, but this bound potentially depends on $k$. Therefore we'd probably also need some assumptions on $F$'s $L^\infty$ behavior.
If there are no such assumptions on $F$ or $z_n$, we can cook up a counterexample. Let $F \equiv 1$ and let $w_n \equiv w \in W_0^{1, q}$ be some smooth bump function. Then let $z_n$ be some sequence in $W_0^{1, q}$ such that $\sup_{x \in \Omega} |z_n| \leq C$ for all $n$, but such that $\|\nabla z_n\|_{L^q} \to \infty$ as $n \to \infty$ (for instance, on $\mathbb{R}$ we could let $z_n$ be something like $\sin(nx)$, perhaps a polygonal version of this). Then the integral above is always over all of $\Omega$ for $k > C$ and in fact it's equal to
$$
\int_{\Omega} |w(x)||\nabla z_n|^q\, dx.
$$
So as long as we choose, say, $w$ to be equal to 1 on some set of large enough measure, this integral will go to infinity as $n \to \infty$.
