# Bound for erf function

For small $\epsilon \geq 0$ Is

$erf(\epsilon) \leq \epsilon$

Can somebody give me the hint

Hint: One definition of the error function is $$\operatorname{erf}(x)=\frac{2}{\sqrt{\pi}}\int_0^xe^{-t^2}\,dt.$$
We always have $e^{-t^2}\le 1$, with equality only at $0$, so for positive $\epsilon$, $$\operatorname{erf}(\epsilon)\lt \frac{2}{\sqrt{\pi}}\epsilon.$$ However, $\dfrac{2}{\sqrt{\pi}}\gt 1$.
And for $t$ close to $0$, $e^{-t^2}$ is very close to $1$. For example, calculate $e^{-t^2}$ for $t=0.01$.