During the factoring of $x^2-1$ I saw a $+x$ and $-x$ were introduced but I wonder how the factoring would go if the $+x-x$ were added in reverse, like so $-x+x$.
I was shown $x^2-1$ can be factored to $(x+1)(x-1)$ thusly...
I want to know how $x^2-1$ can be factored to $(x+1)(x-1)$ if instead of $x^2+x-x-1 =$ the $+x$ and $-x$ were brought in the other way around like so $x^2-x+x-1 =$
I tried to factor this to $(x-1)(x+1)$ and got lost along the way.
I'll start the equation again.
... what happens next?