Kept the equation simple in the title, it's a bit more complicated
The position of the pendulum over time, $ y(t)$, is described by the equation $y=0.3cos(2.214t) + 0.135sin(2.214t) $
When does the pendulum first reach its maximum angle from vertical (hint: you might want to use an inverse trig in your answer)
what is the max angle?
how long after reaching its max angle until the pendulum reaches max deflection in the other direction (hint: where is the next critical point)?
So...I can guess that finding the time when velocity hits 0 would give me the maximum angle of the pendulum, but the equation has two trig functions so I don't know how to solve for $t$...
Since $ y=0.3\cos(2.214t) + 0.135(\sin(2.214t)$, we have
$y'(t) = 2.21 * 0.3 * -sin(2.214t) + 0.135 * 2.214 * cos(2.214t) = -0.663sin(2.214t) + 0.3cos(2.214)$
That's as far as I can get. I cant see any trig identities that could help me isolate t here. Even if I did have such an identity, I don't know how I'd answer part 3 which asks you to find the second time that the velocity = 0 (that makes no sense since solving the velocity equation for 0 should just give you a single t value)